tutoring thread

[o.iatlhawksfan]

Theirs tutoring at my school, and I really want to go, but I don't have a ride back home!</p>

So guess who's gonna tutor me???</p>

</p>

YOU GUYS!!!</p>

 

[Денг Гордон]

Nice....now.</p>

1. Average Rate of Change- Find the average rate of change of f(x) = 1 + sin x over the interval [0. 2pi].</p>

2. Rate of Change- Find the instantaneous rate of change of the surface area S = 6x^2 of a cube with respect to the edge length x at x = a</p>

Not sure how hard/easy it is. I'm supposed to algebraicly solve it. Just drawing the graph, and then using the tangent would be nice...but our book would like us to do it a way that it has absolutely zero examples on how to do it that way. How can there be a rate of change without time?</p>

 

[o.iatlhawksfan]

Can somebody help me with Triangles LOL!</p>

 

[gambitnut]

<div class='quotetop'>QUOTE (o.iatlhawksfan)</div><div class='quotemain'>

Can somebody help me with Triangles LOL!</p>

</div></p>

Postanexampleproblemortwo.</p>

</p>

 

[GMJ]

<div class='quotetop'>QUOTE (BG7 Lavigne)</div><div class='quotemain'></p>

Nice....now.</p>

1. Average Rate of Change- Find the average rate of change of f(x) = 1 + sin x over the interval [0. 2pi].</p>

2. Rate of Change- Find the instantaneous rate of change of the surface area S = 6x^2 of a cube with respect to the edge length x at x = a</p>

Not sure how hard/easy it is. I'm supposed to algebraicly solve it. Just drawing the graph, and then using the tangent would be nice...but our book would like us to do it a way that it has absolutely zero examples on how to do it that way. How can there be a rate of change without time?</p>

</div></p>

1. Get x,y values in that function and then its a matter of getting rise over run. the difference between the x's over the difference in the y's. It won't matter which one you put 'first' (the zero or 2pi value) just as long as your consistent in the numerator and denominator.</p>

2. This requires a derivative for the function. Then plug in A. (hint: 12a)</p>

</p>

 

[pegs]

<div class='quotetop'>QUOTE (BG7 Lavigne)</div><div class='quotemain'></p>

Nice....now.</p>

1. Average Rate of Change- Find the average rate of change of f(x) = 1 + sin x over the interval [0. 2pi].</p>

2. Rate of Change- Find the instantaneous rate of change of the surface area S = 6x^2 of a cube with respect to the edge length x at x = a</p>

Not sure how hard/easy it is. I'm supposed to algebraicly solve it. Just drawing the graph, and then using the tangent would be nice...but our book would like us to do it a way that it has absolutely zero examples on how to do it that way. How can there be a rate of change without time?</p>

</div></p>

algebraically? so does that mean find the derivatives?</p>

if so, it's pretty easy. for the first problem, the derivative rules say the derivative of (one function + another function) = (the derivative of one function) + (the derivative of another function). so you break it down...for the first function, the derivative of a constant is 0 (zero). and for the second function, the derivative of sin is cos.</p>

and for the second problem, you must use the power rule, that says : a*(x^n)= n*a*(x^(n-1)) ; where a=constant, and n=power.</p>

</p>

 

[pegs]

<div class='quotetop'>QUOTE (o.iatlhawksfan)</div><div class='quotemain'></p>

Can somebody help me with Triangles LOL!</p>

</div></p>

http://en.wikipedia.org/wiki/Congruence_(geometry)</p>

Wikipedia helps...you guys should learn to use search engines to help you out. They're a great resource.</p>

If you don't understand anything on Wikipedia, or have googled it and don't understand it, just ask questions. We'd love to help out.</p>

</p>

 

[Денг Гордон]

Thanks very much. Ugh...I was just being dumb on that first one. Got it pretty easily...basic secant slope, y2-y1 / x2-x1....ugh...</p>

That power rule works wonders.</p>

 

[pegs]

how do i find x:</p>

-5sin(5x)=0</p>

</p>

I always have trouble with trig/algebra problems.</p>

 

[Dark Hero]

Anybody here know some Chemistry?</p>

 

[JCB]

<div class='quotetop'>QUOTE (Dark Hero)</div><div class='quotemain'></p>

Anybody here know some Chemistry?</p>

</div></p>

I got a 96 in chem, but that was two years ago. I'd be happy to help if I can remember though.</p>

</p>

 

[JCB]

<div class='quotetop'>QUOTE (peg182)</div><div class='quotemain'></p>

how do i find x:</p>

-5sin(5x)=0</p>

</p>

I always have trouble with trig/algebra problems.</p>

</div></p>

Divide each side by -5. Multiply each side by arcsin (this will cancel the sin on the left side of the equation.) Divide by the five in the original angle. Answer is 0. (I think I did that right. I hated trig)</p>

So:</p>

(-1/5)(-5sin(5x)=0), will get you: sin(5x)=0</p>

(arcsin)(sin(5x)=0), will get you: 5x=0</p>

(1/5)(5x=0), will get you: x=0</p>

</p>

 

[Dark Hero]

First what does this mean PV=nRT</p>

 

[JCB]

<div class='quotetop'>QUOTE (Dark Hero)</div><div class='quotemain'></p>

First what does this mean PV=nRT</p>

</div></p>

P = pressure
V = volume
n = number of moles
R = gas constant (don't remember what it is)
T = temperature in Kelvins</p>

</p>

 

[Dark Hero]

Do you know how to balance equations?</p>

 

[JCB]

<div class='quotetop'>QUOTE (Dark Hero)</div><div class='quotemain'></p>

Do you know how to balance equations?</p>

</div></p>

Yea, if they're not too complex.</p>

</p>

 

[pegs]

<div class='quotetop'>QUOTE (JCB)</div><div class='quotemain'></p>

<div class='quotetop'>QUOTE (peg182)</div><div class='quotemain'></p>

how do i find x:</p>

-5sin(5x)=0</p>

</p>

I always have trouble with trig/algebra problems.</p>

</div></p>

Divide each side by -5. Multiply each side by arcsin (this will cancel the sin on the left side of the equation.) Divide by the five in the original angle. Answer is 0. (I think I did that right. I hated trig)</p>

So:</p>

(-1/5)(-5sin(5x)=0), will get you: sin(5x)=0</p>

(arcsin)(sin(5x)=0), will get you: 5x=0</p>

(1/5)(5x=0), will get you: x=0</p>

</p>

</div></p>

That's why I got! and it didn't work. I have to use this online thing to do homework, and it tells you right away if the answer is wrong. It's so ridiculous, and the way the teacher is running the class is ridiculous.</p>

</p>

 

[Dark Hero]

H2 02------->H2O+O2</p>

 

[JCB]

<div class='quotetop'>QUOTE (peg182)</div><div class='quotemain'></p>

<div class='quotetop'>QUOTE (JCB)</div><div class='quotemain'></p>

<div class='quotetop'>QUOTE (peg182)</div><div class='quotemain'></p>

how do i find x:</p>

-5sin(5x)=0</p>

</p>

I always have trouble with trig/algebra problems.</p>

</div></p>

Divide each side by -5. Multiply each side by arcsin (this will cancel the sin on the left side of the equation.) Divide by the five in the original angle. Answer is 0. (I think I did that right. I hated trig)</p>

So:</p>

(-1/5)(-5sin(5x)=0), will get you: sin(5x)=0</p>

(arcsin)(sin(5x)=0), will get you: 5x=0</p>

(1/5)(5x=0), will get you: x=0</p>

</p>

</div></p>

That's why I got! and it didn't work. I have to use this online thing to do homework, and it tells you right away if the answer is wrong. It's so ridiculous, and the way the teacher is running the class is ridiculous.</p>

</p>

</div></p>

It says that 0 as an answer is wrong? wtf?</p>

</p>

 

[#1_War_Poet_ForLife]

<div class='quotetop'>QUOTE (o.iatlhawksfan)</div><div class='quotemain'></p>

Can somebody help me with Triangles LOL!</p>

</div></p>

</p>

I'll be happy to help</p>

 

[JCB]

<div class='quotetop'>QUOTE (Dark Hero)</div><div class='quotemain'></p>

H2 02------->H2O+O2</p>

</div></p>

2H2 02------->2H2O+O2</p>

I think.</p>

</p>

 

[pegs]

[quote name='JCB']</p>

[quote name='peg182']</p>

[quote name='JCB']</p>

[quote name='peg182']</p>

how do i find x:</p>

-5sin(5x)=0</p>

</p>

I always have trouble with trig/algebra problems.</p>

[/QUOTE]</p>

Divide each side by -5. Multiply each side by arcsin (this will cancel the sin on the left side of the equation.) Divide by the five in the original angle. Answer is 0. (I think I did that right. I hated trig)</p>

So:</p>

(-1/5)(-5sin(5x)=0), will get you: sin(5x)=0</p>

(arcsin)(sin(5x)=0), will get you: 5x=0</p>

(1/5)(5x=0), will get you: x=0</p>

</p>

[/QUOTE]</p>

That's why I got! and it didn't work. I have to use this online thing to do homework, and it tells you right away if the answer is wrong. It's so ridiculous, and the way the teacher is running the class is ridiculous.</p>

</p>

[/QUOTE]</p>

It says that 0 as an answer is wrong? wtf?</p>

</p>

[/QUOTE]</p>

</p>

Yeah, this online homework thing is ridiculous, and this class is ridiculous. I think I'm dropping, mainly because of the fact that the way it's set up, I'm not really learning anything. And the teacher sucks.</p>

 

[cpawfan]

<div class='quotetop'>QUOTE (Dark Hero)</div><div class='quotemain'></p>

H2 02------->H2O+O2</p>

</div></p>

2 hydrogen peroxide molecules breaks down into 2 water molecules and 1 oxygen molecule</p>

The key to solving this is to realize that there must be an even number of water molecules because there will always be an even number of oxygens coming from the peroxide.</p>

</p>

 

[cpawfan]

You don't multiply by arcsin, instead you must perform arcsin on each side</p>

5x=arcsin(0)</p>

 

[pegs]

<div class='quotetop'>QUOTE (cpawfan)</div><div class='quotemain'></p>

You don't multiply by arcsin, instead you must perform arcsin on each side</p>

5x=arcsin(0)</p>

</div></p>

</p>

wouldn't the answer still be zero?</p>

 

[JCB]

<div class='quotetop'>QUOTE (cpawfan)</div><div class='quotemain'></p>

You don't multiply by arcsin, instead you must perform arcsin on each side</p>

5x=arcsin(0)</p>

</div></p>

Pssh, I hate math terms.</p>

Either way, you get 5x=0</p>

</p>

</p>

 

[NJNetz]

Why I am having a hard time with multiplying, dividing, adding radicals? It's like 7th grade math isn't it? That's proof that math is no where close to being one of my strong points.</p>

 

[Dark Hero]

So the one that JCB put is correct?I had something similar to his answer.OK I have a few things that I don't know what they are Temperature Scale, Acid and Base, gas law and conservation of mass.</p>

 

[cpawfan]

Remember sin(0) = 0, sin(pi) = 0, sin(2pi) = 0 etc</p>

There are multiple solutions for x</p>

 

[cpawfan]

<div class='quotetop'>QUOTE (Dark Hero)</div><div class='quotemain'></p>

So the one that JCB put is correct?I had something similar to his answer.OK I have a few things that I don't know what they are Temperature Scale, Acid and Base, gas law and conservation of mass.</p>

</div></p>

Yes, it is correct</p>

Go ahead and fire away.</p>

</p>